Extra Questions for Class 6 Maths revision becomes an easy task during the annual exam. Students who find it challenging to understand the basics of the chapter must practice all the essential questions to understand better. These crucial questions and answers on Algebra Class 6 Maths can aid the students’ preparation through the concepts of this chapter 11. https://meritbatch.com/algebra-class-6-extra-questions/
Algebra Class 6 Extra Questions Maths Chapter 11
Extra Questions for Class 6 Maths Chapter 11 Algebra
Algebra Class 6 Extra Questions Very Short Answer Type
Algebra Questions For Class 6 Question 1.
Six less than a number equals to two. What is the number?
Solution:
Let the number be ‘x’.
According to condition, we have x – 6 = 2
By inspections, we have 8 – 6 = 2
∴ x = 8
Thus, the required number is 8.
Algebra Class 6 Extra Questions Question 2.
Write an algebraic expression for each of the following:
(a) 3 subtracted from a number y.
(b) 5 is added to three times a number x.
Solution:
(a) The required expression is y – 3
(b) The required expression is 5 + 3x
Class 6 Algebra Extra Questions Question 3.
Write an algebraic expression for the following expressions:
(a) The sum of a number x and 4 is doubled.
(b) One fourth of a number x is added to one third of the same number.
Solution:
(a) The required expression is 2 x (x + 4)
(b) The required expression is \(\frac { 1 }{ 4 }\)x + \(\frac { 1 }{ 3 }\)x
Algebra Class 6 Questions Question 4.
Think of a number x. Multiply it by 3 and add 5 to the product and subtract y subsequently. Find the resulting number.
Solution:
Required number is (3x + 5)
Now we have to subtract y from the result i.e., 3x + 5 – y
Class 6 Maths Chapter 11 Extra Questions Question 5.
Here is a pattern of houses with matchsticks:
Write the general rule for this pattern.
Solution:
One house is made of 6 matchsticks i.e. 6 x 1
Two houses are made of 12 matchsticks i.e. 6 x 2
Three houses are made of 18 matchsticks i.e. 6 x 3
∴ Rule is 6n where n represents the number of houses.
Algebra Extra Questions For Class 6 Question 6.
If the side of an equilateral triangle is x, find its perimeter.
Solution:
We know that the three sides of an equilateral triangle are equal.
∴ x + x + x = 3x.
Thus, the required perimeter = 3x units.
Algebraic Expressions Class 6 Question 7.
If x = 3, find the value of the following:
(i) x + 5
(ii) 2x – 3
(iii) x – 7
(iv) \(\frac { x }{ 3 }\) – 1
Solution:
Given that x = 3
(i)x + 5 = 3 + 5 = 8
(ii) 2x – 3 = 2 x 3 – 3 = 6 – 3 = 3
(iii) x – 7 = 3- 7 = -4
(iv) \(\frac { x }{ 3 }\) – 1 = \(\frac { 3 }{ 3 }\) -1 = 1 – 1 = 0
Algebra Class 6 Worksheet Question 8.
If x = 2, y = 3 and 2 = 5, find the value of;
(a) 2x + y + z
(b) 4x -y + z
(c) x – y + z
Solution:
(a) Given that: x – 2, y = 3 and z = 5
∴ 2x + y + 2 = 2 x 2 + 3 + 5
= 4 + 3 + 5 = 12
(b) 4x – y + z = 4 x 2 – 3 + 5
= 8 – 3 + 5 = 5 + 5 = 10
(c) x – y + z = 2 – 3 + 5 = -1 + 5 = 4
Algebra Sums For Class 6 Question 9.
State which of the following are equations with a variable?
(a) 12 = x – 5
(b) 2x > 7
(c) \(\frac { x }{ 2 }\) = 5
(d) 5 + 7 = 3 + 9
(e) 7 = (11 x 5) – (12 x 4)
Solution:
(a) 12 = x – 5 is an equation with a variable x.
(b) 2x > 7 is not an equation because it does not have ‘=’ sign.
(c) \(\frac { x }{ 2 }\) = 5 is an equation with a variable x.
(d) 5 + 7 = 3 + 9 is not an equation because it has no variable.
(e) 7 = (11 x 5) – (12 x 4) is not an equation because it has no variable.
Class 6 Maths Algebra Extra Questions Question 10.
Think of a number, add 2 to it and then multiply the sum by 6, the result is 42.
Solution:
Let the number be x.
∴ Sum of x and 2 = x + 2
Now by multiplying the sum by 6, we get
6 × (x + 2) = 42
⇒ 6 × x + 6 × 2 = 42
⇒ 6x + 12 = 42
By inspection, we get
6 × 5 + 12 = 42
⇒ 30 + 12 = 42
∴ 42 = 42
So, the required number = 5
Algebra Class 6 Extra Questions Short Answer Type
Algebra Worksheet For Class 6 Question 11.
The side of a regular hexagon is s cm. Find its perimeter.
Solution:
Each side of a regular hexagon = s
∴ its perimeter = s + s + s + s + s + s = 6s cm
Question 12.
If a = 3, b = \(\frac { 1 }{ 2 }\) and c = \(\frac { 1 }{ 4 }\), find the value of
Solution:
Class 6 Algebra Questions Pdf Question 13.
Complete the table and find the solution of the equation 19 – x = 13
Solution:
By inspection, we have
Thus, the required solution is 6.
Class 6th Algebra Questions Question 14.
If x = –\(\frac { 1 }{ 2 }\), y = \(\frac { 1 }{ 4 }\) and z = 0, find the value of the given expressions
(a) 8z + 2x -y
(b) z – y + 3x
Solution:
Class 6 Maths Ch 11 Extra Questions Question 15.
Fill in the blanks:
(a) 5 added to -5 = ……….
(b) If x = 3, then 3x – 5 = ……….
(c) If x = 1 and y = 2, then 2x + 3y = ……….
(d) If 10x – 6 = 14, then x = ……….
(e) 4 less than a number x = ……….
Solution:
(a) 0
(b) 4
(c) 8
(d) 2
(e) x – 4
Algebra Class 6 Extra Questions Higher Order Thinking Skills (HOTS)
Class 6 Linear Equations Extra Questions Question 16.
A starts his car from Delhi at 6.00 am to Amritsar. The uniform speed of his car is x km/h. At 12.00 noon, he finds that he is still 50 km away from Amritsar. Find the distance between Delhi and Amritsar.
Solution:
Time taken by A to reach Amritsar = 12.00 noon – 6.00 am = 6 hour.
The uniform speed of the car = x km/ hr
∴ Total distance covered by A = Time x speed = 6x km.
∴ Distance between Delhi and Amritsar = (6x + 50) km.
Algebra Questions Class 6 Question 17.
Anshika’s Score in Science is 15 more than the two-third of her score in Sanskrit. If she scores x marks in Sanskrit, find her score in Science.
Solution:
Anshika’s score in Sanskrit = x
∴ Her marks in Science = \(\frac { 2 }{ 3 }\)x +15
∴ Thus, Anshika’s score in Science = \(\frac { 2 }{ 3 }\)x + 15