Solving ICSE Class 10 Physics Previous Year Question Papers ICSE Class 10 Physics Question Paper 2016 is the best way to boost your preparation for the board exams.

ICSE Class 10 Physics Question Paper 2016 Solved

Time: 1½ hours
Maximum Marks: 80

General Instructions:

  • Answers to this Paper must be written on the paper provided separately.
  • You will not be allowed to write during the first 15 minutes.
  • This time is to be spent in reading the Question Paper,
  • The time given at the head of this Paper is the time alloted for writing the answers.
  • Attempt all questions from Section I and any four questions from Section II.
  • The intended marks of questions or parts of questions are given in brackets [ ].

SECTION – I (40 Marks)
Attempt all questions from this Section

Question 1.
(a) (i) Give an example of a non contact force which is always of attractive nature.
(ii) How does the magnitude of this non contact force on the two bodies depend on the distance of separation between them? [2]
Answer:
(i) Gravitational force
(ii) F α \(\frac{1}{r^2}\)

(b) A boy weighing 40 kgf climbs up a stair of 30 steps each 20 cm high in 4 minutes and a girl weighing 30 kgf does the same in 3 minutes. Compare:
(i) The work done by them.
(ii) The power developed by them. [2]
Answer:
(i) Equal work.
(ii) Power developed by the girl is more as she does the same work as the boy but is lesser time.

(c) With reference to the terms Mechanical Advantage, Velocity Ratio and efficiency of a machine, name and define the term that will not change for machine of a given design. [2]
Answer:
Velocity ratio:
It is defined as the ratio of the velocity of the effort (vE) to the velocity of the resistance force (Load) (vL).

(d) Calculate the mass of ice required to lower the temperature of 300 g of water 40°C to water at 0°C. [2]
(Specific latent heat of ice = 336 J/g, Specific heat capacity of water = 4.2J/g°C)
Answer:
Given,
Mass of water = 300 g
Initial temperature = 40°C
Final temperature = 0°C
Let the mass of ice = m g
∴ Heat to be removed to lower the temperature of 300 g of water from 40°C to 0°C
= 300 × 4.2 × (40 – 0) J
= 300 × 4.2 × 40 J = 50400 J.
Heat lost by ice from 40 °C to 0°C of water
= (m × 336) J.
By principle of calorimetry,
m × 336 = 50400
Therefore, m = \(\frac{50400}{336}\) = 150g

(e) What do you understand by the following statements:
(i) The heat capacity of the body is 60JK1.
(ii) The specific heat capacity of lead is 130 Jkg‘1K’1. [2]
Answer:
(i) It means 60 J of heat is required to raise its temperature by 1 K.
(ii) It means 130 J of heat is required to raise the temperature of 1 kg of lead through 1K.

ICSE 2016 Physics Question Paper Solved for Class 10

Question 2.
(a) State two factors upon which the heat absorbed by a body depends. [2]
Answer:

  1. Nature of material and
  2. Temperature of the body.

(b) A boy uses blue colour of light to find the refractive index of glass. He then repeats the experiment using red colour of light. Will the refractive index be the same or different in the two cases? Give a reason to support your answer. [2]
Answer:
No, the refractive index of a medium depends upon the colour of light used. As n = \(\frac{\mathrm{c}}{\mathrm{v}}\) and different colours have different speed in a medium, therefore, n is different.

(c) Copy the diagram given below and complete the path of the light ray till it emerges out of the prism. The critical angle of glass is 42°. In your diagram mark the angles wherever necessary. [2]
ICSE 2016 Physics Question Paper Solved for Class 10 2
Answer:
The diagram is as shown :
ICSE 2016 Physics Question Paper Solved for Class 10 3

(d) State the dependence of angle of deviation:
(i) On the refractive index of the material of the prism.
(ii) On the wavelength of light [2]
Answer:
(i) Directly proportional to the refractive index of the material of the prism.
(ii) Inversely proportional to the wavelength of light used.

(e) The ratio of amplitude of two waves is 3:4. What is the ratio of their:
(i) loudness?
(ii) Frequencies? [2]
Answer:
(i) \(\frac{L_1}{L_2}=\left(\frac{3}{4}\right)^2=\frac{6}{16}\)
(ii) 1 : 1

Question 3.
(a) State two ways by which the frequency of transverse vibrations of a stretch string can be increased. [2]
Answer:

  1. By increasing the tension in the string and
  2. Decreasing the length of the string.

(b) What is meant by noise pollution? Name one source of sound causing noise pollution. [2]
Answer:
Unpleasant sounds are called noise. Some of the main ‘noise polluters’ are aircraft, road traffic, greatly amplified music.

(c) The V-I graph for a series combination and for a parallel combination of two resistors is shown in the figure below. Which of the two A or B. represents the parallel combination? Give reasons for your answer. [2]

ICSE 2016 Physics Question Paper Solved for Class 10 4
Answer:
Resistance in parallel combination is less than in series combination for the same set of resistors. The slope of the graph gives the value of resistance. Graph A has less slope and has less resistance, therefore, it represents parallel combination.

(d) A music system draws a current of 400 mA when connected to a 12 V battery. [2]
(i) What is the resistance of the music system?
(ii) The music system if left playing for several hours and finally the battery voltage drops to 320 mA and the music system stops playing when the current.
Answer:
Given, I = 400 mA, V = 12 V, R = ?
R = \(\frac{V}{I}=\frac{12}{400 \times 10^{-3}}\) = 30 Ω
V = IR = 320 × 10-3 × 30
= 9.6 V

(e) Calculate the quantity of heat produced in a 20 Ω resistor carrying 2.5 A current in 5 minutes. [2]
Answer:
Given, R = 20 W, I = 2.5 A, t = 5 min = 300 s
Using H = I2Rt
= (2.5)2 × 20 × 300
= 37500 J

ICSE 2016 Physics Question Paper Solved for Class 10

Question 4.
(a) State the characteristics required of a good thermion emitter. [2]
Answer:

  1. The emitter metal should have high melting point so that it can be operated at a high temperature to achieve appreciable emission of electrons.
  2. The value or work function of the emitter metal should be as low as possible.

(b) An element ZSA decays to 85R222 after emitting 2 a particles and 1 P particle. Find the atomic number and atomic mass of the element S. [2]
Answer:
The decay will follow the following sequence
ICSE 2016 Physics Question Paper Solved for Class 10 1
Therefore, we have
Z – 3 = 85 or Z = 85 + 3 = 88
And A – 8 = 222 or A = 222 + 8 = 230
Z = 88, A = 230

(c) A radioactive substance is oxidized. Will there be any change in the nature of its radioactivity? Give a reason for your answer. [2]
Answer:
No, radioactivity is not affected by any physical process.

(d) State the characteristics required in a material to be used as an effective fuse wire. [2]
Answer:
The material should have high resistivity and low melting point.

(e) Which coil of a step up transformer is made thicker and why? [2]
Answer:
Primary, as it has lesser number of turns.

SECTION – II (40 Marks)
(Attempt any four questions from this Section)

Question 5.
(a) A stone of mass ‘m’ is rotated in a circular path with a uniform speed by tying a strong string with the help of your hand. Answer the following questions : (3)
(i) Is the stone moving with a uniform or variable speed ?
(ii) Is the stone moving with a uniform acceleration ? In which direction does the acceleration act?
(iii) What kind of force acts on the hand and state its direction ?
Answer:
(i) Uniform speed.
(ii) Yes, towards the centre of the circular path.
(iii) Centrifugal outwards.

(b) From the diagram given below, answer the question that follow : (3)
ICSE 2016 Physics Question Paper Solved for Class 10 6
(i) What kind of pulleys are A and B ?
(ii) State the purpose of pulley B.
(iii) What effort has to be applied at C just raise the load L = 20 kgf ?
(Neglect the weight of pulley A and friction)
Answer:
(i) A – Single movable, B – Single fixed.
(ii) It changes the direction of force.
(iii) Distance moved by load dL = x/2.
Distance moved by the effort dE = x
Load = 20 kg f, Effort = ?
Now, Load × dL = Effort × dE
20 × x/2 = Effort × x
or Effort = 10 kg f

(c) (i) An effort is applied on the bigger wheel of a gear having 32 teeth. It is used to turn a wheel of 8 teeth. Where it is used.
(ii) A pulley system has three pulleys. A load of 120 N is overcome by applying an effort of 50 N.
Calculate the Mechanical Advantage and Efficiency of this system. (4)
Answer:
(i) It is used to gain speed.
= \(\frac{\text { Number of teeth in the driver }}{\text { Number of teeth in the driven }}\)
= \(\frac{\mathrm{N}_{\mathrm{A}}}{\mathrm{N}_{\mathrm{B}}}=\frac{32}{8}\) = 4

(ii) Given, L = 120 N, E = 50 N, MA = ?, η = ?
MA = \(\frac{\mathrm{L}}{\mathrm{E}}=\frac{120}{50}\) = 2.4
Velocity ratio is equal to the number of pulleys, hence
η = \(\frac{\mathrm{MA}}{\mathrm{VR}}=\frac{2.4}{3}\) = 0.8

ICSE 2016 Physics Question Paper Solved for Class 10

Question 6.
(a) (i) What is the principle of method of mixtures ? (3)
(ii) What is the other name given to it ?
(iii) Name the law on which the principle is based
Answer:
(i) “Heat lost by the hot body is equal to the heat gained by the cold body”.
(ii) Principle of calorimetry.
(iii) Law of conservation of energy.

(b) Some ice is heated at a constant rate, and its temperature is recorded after every few seconds, till steam is formed at 100°C. Draw a temperature time graph to represent the change. Label the two phase changes in your graph. (3)
Answer:
The figure for phase change is shown below :
ICSE 2016 Physics Question Paper Solved for Class 10 2

(c) A copper vessel of mass 100 g contains 150 g of water at 50°C. How much ice is needed to cool it to 5°C ? (4)
Given : Specific heat capacity of copper = 0.4 Jg-1 °C-1
Specific heat capacity of water = 4.2 Jg-1 °C-1
Specific latent heat of fusion ice = 336 Jg-1
Answer:
Given,
Mass of ice = m g
Mass of copper vessel = 100 g
Mass of water = 150 g
Initial Temperature = 50 °C
Final temperature = 5 °C
Now, we have
Heat lost by water due to decrease in temperature from 50°C to 5°C
= 150 × 4.2 × (50 – 5)
= 28350 J
Heat lost by the calorimeter
= 100 × 0.4 × (50 – 5) J
= 1800 J
Heat gained by ice = m × 336 × (5 – 0) J
= 1680m J
Total heat lost by the water + Calorimeter
= (28350 + 1800) J
= 30150 J
By principle of calorimetry,
Heat lost by water and calorimeter = heat gained by the ice
30150 = 1680 m
m = \(\frac{30150}{1680}\) = 17.94 g

Question 7.
(a) (i) Write a relationship between angle of incidence and angle of refractions for a given pair of media. (3)
(ii) When a ray of light enters from one medium to another having different optical densities it bends. Why does this pehnomenon occur ?
(iii) Write one conditions where it does not bend when entering a medium of different optical density.
Answer:
(i) The relation is n = \(\frac{\sin i}{\sin r}\)
(ii) This occurs because light has different velocities in different media. The change in velocity causes the bending of light.
(iii) When it enters perpendicular to the interface separating the two media.

(b) A lens produces a virtual image between the object and the lens. (3)
(i) Name the lens.
(ii) Draw a ray diagram to show the formation of this image.
Answer:
(i) Concave lens.
(ii) The ray diagrams is a shown :
ICSE 2016 Physics Question Paper Solved for Class 10 8

(c) What do you understand by the term ‘Scattering of light’ ? Which colour of white light is scattered the least and why ? (4)
Answer:
Light scattering is the deflection of a ray of light from a straight path, for example by irregularities in the propagation medium, particles, or in the interface between two media.

Red colour is scattered the least because scattering of light depends inversely upon the four power of wavelength. As red colour has the maximum wavelength in the visible region, therefore, it scattered the least.

ICSE 2016 Physics Question Paper Solved for Class 10

Question 8.
(a) (i) Name the waves used for echo depth sounding.
(ii) Give one reason for their use for the above purpose.
(iii) Why are the waves mentioned by you not audible to us ? (3)
Answer:
(i) Ultrasonic.
(ii) Easier to transmit through water.
(iii) Because their frequency is greater than 20 kHz the upper limit of our audible range.

(b) (i) What is an echo
(ii) State two conditions for an echo to take place. (3)
Answer:
(i) An echo is the phenomenon of repetition of sound of a source by reflection from an obstacle.
(ii) Presence of a solid reflecting material and the distance between the obstacle and the source of sound should be such that it takes the reflected sound at least 0.1 s to reach the source.

(c) (i) Name the phenomenon involved in tuning a radio set to a particular station.
(ii) Define the phenomenon named by you in part (i) above.
(iii) What do you understand by loudness of sound ?
(iv) In which units is the loudness of sound measured ? (3)
Answer:
(i) Resonance.
(ii) Resonance or acoustic resonance is a special case of forced vibrations. It occurs when the frequency of the applied periodic external force becomes equal to the natural frequency of the vibrating body.
(iii) Loudness is the degree of sensation of sound produced. It depends upon the intensity of sound waves near the ear and response (sensitivity) of the ear for the waves of that frequency.
(iv) The unit of loudness is phon.

Question 9.
(a) (i) Which particles are responsible for current in conductors ?
(ii) To which wire of a cable in a power circuit should the metal case of a geyser be connected ? (3)
Answer:
(i) Electrons
(ii) Earth wire
(iii) Live wire

(b) (i) Name the transformer used in the power transmitting station of a power plant.
(ii) What type of current is transmitted from the power station
(iii) At what voltage is this current available to our household ? (3)
Answer:
(i) Step up transformer
(ii) Alternating current of low value.
(iii) 220 V

(c) A battery of emf 12 V and internal resistance 2 Ω is connected with two resistors A and B of resistance 4 Ω and 6 Ω. respectively joined in series. (4)
ICSE 2016 Physics Question Paper Solved for Class 10 9
Find:
(i) Current in the circuit
(ii) The terminal voltage of the cell.
(iii) The potential difference across 6 Ω Resistor.
(iv) Electrical energy spent per minute in 4 Ω resistor.
Answer:
Total resistance in the circuit
R = 4 + 6 + 2
= 12 Ω
(i) I = V / R = 12 / 12 = 1 A
(ii) V = E – Ir = 12 – 1 × 2 = 10 V
(iii) V = IR = 1 × 6 = 6V
(iv) E = I2 R t = (1)2 × 4 × 60 = 240 J

ICSE 2016 Physics Question Paper Solved for Class 10

Question 10.
(a) Arrange α, β, and γ rays in ascending order with respect to their (3)
(i) Penetrating power.
(ii) Ionising power.
(iii) Biological effect.
Answer:
(i) Alpha, Beta and Gamma.
(ii) Gamma, Beta and Alpha.
(iii) Gamma, Beta and Alpha.

(b) (i) In a cathode ray tube what is the function of anode ?
(ii) State the energy conversion taking place in a cathode ray tube.
(iii) Write one use of cathode ray tube.
Answer:
(i) It accelerates the electrons along the highly evacuated tube and also focus them into a narrow beam.
(ii) Heat energy into kinetic energy of electrons.
(iii) Picture tube in television.

(c) (i) Represent the change in the nucleus of a radioactive element when a P particle is emitted.
(ii) What is the name given to elements with same mass number and different atomic number.
(iii) Under which conditions does the nucleus of an atom tend to radioactive ?
Answer:
(i) The change is as shown
\({ }_{\mathrm{Z}}^{\mathrm{A}} \mathrm{P} \rightarrow{ }_{\mathrm{Z}+1}^{\mathrm{A}} \mathrm{D}+{ }_{-1}^0 e\)
(ii) Isobars.
(iii) When the nucleus is unstable.