Solving ICSE Class 10 Computer Applications Previous Year Question Papers ICSE Class 10 Computer Applications Question Paper 2021 Semester 1 is the best way to boost your preparation for the board exams.
ICSE Class 10 Computer Applications Question Paper 2021 Solved Semester 1
Maximum Marks: 50
Time allowed: 1 hour
General Instructions:
- You will not be allowed to write during the first 10 minutes.
- This time is to be spent in reading the question paper.
- ALL QUESTIONS ARE COMPULSORY.
- The marks intended for each question are given in brackets [ ].
Select the correct option for each of the following questions.
Question 1.
Choose the correct answer:
(i) The blueprint that defines the variables and the methods common to all of a certain kind is termed as: [1]
(a) class
(b) object
(c) package
(d) method
Answer:
(a) class
(ii) A data type which contains integer as well as fractional part and occupies 32 bits space is: [ 1 ]
(a) float
(b) char
(c) double
(d) byte
Answer:
(a) float
(iii) What is the final value stored in variable x? double x = Math, ceil (Math.abs(-7.3)); [1]
(a) 7.0
(b) 8.0
(c) 6.0
(d) 9.0
Answer:
(b) 8.0
(iv) Which of the following keyword is used to create symbolic constants in Java ? [1]
(a) final
(b) Final
(c) Constant
(d) Const
Answer:
(a) final
(v) Name the type of error in the statement given below: [ 1 ]
double x;y;z;
(a) Logical error
(b) Syntax error
(c) Runtime error
(d) No error
Answer:
(b) Syntax error
Question 2.
Fill in the blanks with the correct options :
(i) The keyword to create an object of a class is ………………… . [ 1 ]
(a) create
(b) new
(c) New
(d) NEW
Answer:
(b) new
(ii) The operator which acts on one operand is known as ………………… . [1]
(a) binary
(b) ternary
(c) unary
(d) relational
Answer:
(c) unary
(iii) The ASCII code of ‘B’ is ………………… . [1]
(a) 67
(b) 66
(c) 98
(d) 99
Answer:
(b) 66
(iv) A ………………….. method needs to be called with help of an object. [1]
(a) void
(b) class
(c) non-static
(d) static
Answer:
(c) non-static
(v) Parameters used in the method call statement are ………………… [1]
(a) Actual parameters
(b) Informal parameters
(c) Formal parameters
(d) Void parameters
Answer:
(a) Actual parameters
Question 3.
Name the following:
(i) The concept of having more than one constructor with different types of parameters: [ 1 ]
(a) Copy constructor
(b) Method overloading
(c) Constructor overloading
(d) Overloaded methods
Answer:
(c) Constructor overloading
(ii) The keyword which indicates that the method returns no value: [1].
(a) public
(b) static
(c) void
(d) abstract
Answer:
(c) void
(iii) The process of binding the data and method together as one unit is called as : [1]
(a) Encapsulation
(b) Inheritance
(c) Polymorphism
(d) Dynamic binding
Answer:
(a) Encapsulation
(iv) The jump statement that is used inside a switch case construct to terminate a statement sequence: [ 1 ]
(a) continue
(b) break
(c) return
(d) goto
Answer:
(b) break
(v) The program code written in any high-level language to solve a problem is: [ 1 ]
(a) object code
(b) source code
(c) machine code
(d) bytecode
Answer:
(b) source code
Question 4.
State whether the statement is True or False:
(i) char is a non-primitive data type. [1]
(a) True
(b) False
Answer:
(b) False
(ii) Multi line comments in Java start with /* and end with */. [1]
(a) True
(b) False
Answer:
(a) True
(iii) == is an assignment operator. [1]
(a) True
(b) False
Answer:
(b) False
(iv) Java compiler automatically creates a default constructor in case no constructor is present in the java class. [1]
(a) True
(b) False
Answer:
(a) True
(v) System.exit(0) terminates the program from any point. [1]
(a) True
(b) False
Answer:
(a) True
Question 5.
Choose the odd one: [1]
(i) (a) >=
(b) %
(c) /
(d) *
Answer:
(d) *
(ii) (a) double [1]
(b) int
(c) char
(d) String
Answer:
(d) String
(iii) (a) if else [1]
(b) if
(c) switch case
(d) while()
Answer:
(d) while()
(iv) (a) nextInt() [1]
(b) nextDouble()
(c) nextString
(d) next()
Answer:
(c) nextString
(v) (a) Robust [1]
(b) Platform Independent
(c) Inheritance
(d) Multihreading
Answer:
(c) Inheritance
Question 6.
Give the output of the following:
(i) int x = 2, y = 4,z = 1; [1]
int result =(++z) + 7 + (++x) + (Z++)i
(a) 11
(b) 12
(c) 10
(d) 9
Answer:
(a) 11
(ii) intx; [1]
for (x = 1; x < = 3; x + +);
System. out.print(x);
(a) 123
(b) 123 4
(c) 4
(d) 1
Answer:
(c) 4
(iii) intf=10,m=9;
Stringe=(m%f==9) ? “YES”: “NO”;
System.out.print (e);
(a) YES
(b) NO
(c) YESNO
(d) NOYES
Answer:
(a) YES
(iv) switch(x){
case M’:
System. out.print(”Microsoft Teams “);
break;
case ‘G’;
System.out.print(“Google Meet”);
default:
System.out.print(“Any software”); }
break;
case W:
System.out.print(“Web Ex”);
break;
}
When x = ‘g’
(a) Google Meet
(b) Any software
(c) Google Meet
Any software
(d) WebEx
Answer:
(b) Any software
(v) int v = 5;
while (- v >= 0) {
System.out.prmt(v);
)
(a) 43210
(b) 54321
(c) 543210
(d) 4321
Answer:
(a) 43210
Question 7.
Given below is a class with following spec ijications:
class name : Number
void Display(int n) – To extract and print each digit of given number from last digit of the first digit on separate lines.
Example: n = 674
Output
4
7
6
void Display() – To print numbers from 0.5 to 5.0 with updation of 0.5.
Fill in the blanks of the given program with appropriate statements.
class (i) __________
{
void Display (int n) {
while ((ii) __________ )
{
int rem=(iii)
System.out.println(rem);
n=(iv) __________
}
void Display() {
for(v)__________;x <= (vi)__________;x + = 0.5)
System.out.println(x);
}
}
(i) (a) Number [1]
(b) number
(c) NUMBER
(d) NUM
Answer:
(a) Number
(ii) (a) n < 0 [1]
(b) n > 0
(c) n == 0
(d) n = 0
Answer:
(b) n > 0
(iii) (a) n %100 [1]
(b) n/10;
(e) n%10;
(d) n/100
Answer:
(c) n%10;
(iv) (a) n%10; [1]
(b) n/10;
(c) n/100;
(d) n%100
Answer:
(b) n/10;
(v) (a) double x = 0.5
(b) Double x = 0.5
(c) double x = 0.0
(d) Double x = 0.0
Answer:
(a) double x = 0.5
(vi) (a) x >= 5.0 [1]
(b) x <= 5.0
(c) x == 5.0
(d) x = 5.0
Answer:
(b) x <= 5.0
Question 8.
A school is giving away merit certificates for the students who have scored 90 percentage and above in class 10.
The following program is based on the specification given below. Fill in the blanks with appropriate Java statements.
class name : Student
Member variables:
String name: To enter name of a student
double per: To enter perentage obtained by the student
String cer: To store the message
Member method
void input (): To accept the detail
void merit (): To check the percentage and award the merit
void display (): To display the detail
void main (): To create an object of the class and invoke the methods
import java.(i) __________. *;
class Student {
String name; double per;
String cer; void inputQ {
Scanner obj=new Scanner (System.in);
System.out.printlh(”Enter name, Percentage”);
name = obj.next();
per=(ii) __________
}
void merit()
{
if ((iii) __________ )
{
cer="AWARDED";
}
else
cer=(iv) __________
}
void(v) __________
{
System, out.println(name);
System.out.println(per);
System.out.println(cer);
}
void main(){
Student s = new (vi) __________
s.input();
s.merit();
s.display();
}
}
(i) (a) utility [1]
(b) Util
(c) util
(d) UTILITY
Answer:
(c) util
(ii) (a) obj.nextDouble(); [1]
(b) nextDouble();
(c) obj.nextFloat();
(d) nextFloat()
Answer:
(a) obj.nextDouble();
(iii) (a) per>=90 [1]
(b) per<=90
(c) per>90
(d) per==90
Answer:
(a) per>=90
(iv) (a) NOT AWARDED; [1]
(b) “NOT AWARDED”
(c) “AWARDED”;
(d) “NOT AWARDED”
Answer:
(b) “NOT AWARDED”;
(v) (a) display() [1]
(b) Display()
(c) Print()
(d) DISPLAY()
Answer.
(a) display()
(vi) (a) Student(); [1]
(b) STUDENT()
(c) student()
(d) Student()
Answer:
(a) Student();
Question 9.
The following program segment checks whether number is an Abundant number or not. A number is said to be an Abundant number when the sum of its factors (excluding the number itself) is greater than the number.
Example:
Factors of number 12 are 1, 2, 3, 4, 6
Sum of factors is 1 + 2 + 3 + 4 + 6 = 16
Fill in the blanks with appropriate java statements void abundantfint n)
{int s = 0;
for((i) ________ ; (ii) ________ ; i++)
{ if((iii) _________)
s=s+i;}
if((iv)_________)
System.out.println(“Abundant Number”);
else
System.out.println(“Not Abundant Number”);
}
(i) (a) int i = 1 [1]
(b) int i = 0
(c) int i = 2
(d) Int i = 1
Answer:
(a) int i = 1
(ii) (a) i <= n [1]
(b) i < n
(c) i > n
(d) i >= n
Answer.
(b) i < n
(iii) (a) n%i == 0 [1]
(b) n%i == 1
(c) n%2 == 0
(d) n/2 == 0
Answer.
(a) n%i == 0
(iv) (a) s < n
(b) s > n
(c) s == n
(d) s = n
Answer:
(b) s > n
Question 10.
Read the following case study and answer the questions given below by choosing the correct option:
Java compilation is different from the compilation of other high-level languages. Other high-level languages use interpreter or compiler but in Java, the source code is first compiled to produce an intermediate code called the byte code, this byte code is platform independent and is a highly optimized set of instructions designed to be executed by Java in the run time system called JVM (Java Virtual Machine), JVM is a Java interpreter loaded in the computer memory as soon as Java is loaded JVM is different for different platforms.
(i) Full form of JVM is: [1]
(a) Java Visual Machine
(b) Joint Vision Mechanism
(c) Java Virtual Machine
(d) Java virtual mechanism
Answer:
(c) Java Virtual Machine
(ii) JAVA code is: [1]
(a) Compiled and interpreted
(b) Only compiled
(c) Only Interpreted
(d) Translated
Answer:
(a) Compiled and interpreted
(iii) JAVA source code is compiled to produce: [ 1 ]
(a) Object code
(b) Byte code
(c) Final code
(d) Machine code
Answer:
(b) Byte code
(iv) JVM is an/a __________ . [1]
(a) Interpreter
(b) Compiler
(c) Intermediate-code
(d) High level language
Answer:
(a) Interpreter